Implement pow(x, n).
def myPow(_x: Double, _n: Int): Double = { var (x, n) = (_x, _n) if (x == 0) 0 if (n == 0) 1 else { if (n < 0) { x = 1 / x n = -n } var pow = 1 while (n > 0) { if ((n & 1) == 1) { pow *= x } x *= x n <<= 1 } pow } }
Last updated 6 years ago